New problemo
Since u guys r boring and don't like challenges, no big prize on this one q_q
(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fpuu.sh%2FhJ5Sa%2Fd09fe23a59.png&hash=596439b34db7ed7970fe98b70e9f5e2d)
lets make it 2 for the helluvit
(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fpuu.sh%2FhJ5Xv%2F38659d4458.png&hash=bca288e017925d8015edd980dcacb831)
Please only use YOUR brain to answer, unless I specify you're allowed a calculator on a specific problem.
i hate you.. you made me do some mathWhy did I discover this topic just now :(
but anyway the answer is x=3.5
i need to write this on the pc to take a screenshot so i'll post the way later because idk how to do math on computer progarmms so it is going to take me some time ;)
edit: sorry i had to re-upload it because there were some mistakes. and sorry for the bad writing, it is hard to write using a pin and a pad for laptop :)
(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fi62.tinypic.com%2F1zwojgj.png&hash=8c36299752c95e76236bd9ae775bc189)
You guys SUCK at vectors.
All you have to do is transform the equations to their vectors, dot product all of them, and find which pair's dot product is equal to zero (making them orthogonal, otherwise known as 90 degrees from eachother).
You guys have till April 10 to submit an answer with explanation. Then, the first submission with a correct response and sufficient reasoning will be granted the prize.
This problem can be solved without calculus, for those confused by the derivative in the above solution^
You can submit multiple attempts if you wish.
In the event of no correct response, I will grant 1 additional day with a false answer choice that has been achieved eliminated.
GL
I'm glad that there are people alive that understand this stuff.Show us the almighty Irfan brain :kappa:
Dank job by Nany499
Instead of going for the the derivative, you could use the formula for the vertex of a quadratic in the form ax^{2}+bx+c which is (-b/2a, f(-b/2a)) (derived from the derivative)
If you see me logged in game/on forums, message me and ask for your prize.
New one will be up soon.
ay guise r we ded alredy? Literally free 2m waiting to be taken
If you're leaning towards non-calculus questions, please let me know.
I believe that Calculus questions aren't really doing no good on the topic :P.64/75 ?
I'd like to offer a question of my own though, if I may, to get the brain going;
(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fi.imgur.com%2FJ4IoJFj.jpg&hash=dfe004cb9d9395d4e902fd5b2dd7c659)
May I ask how you got that? :PI believe that Calculus questions aren't really doing no good on the topic :P.64/75 ?
I'd like to offer a question of my own though, if I may, to get the brain going;
(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fi.imgur.com%2FJ4IoJFj.jpg&hash=dfe004cb9d9395d4e902fd5b2dd7c659)
I believe that Calculus questions aren't really doing no good on the topic :P.
I'd like to offer a question of my own though, if I may, to get the brain going;
(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fi.imgur.com%2FJ4IoJFj.jpg&hash=dfe004cb9d9395d4e902fd5b2dd7c659)
Looks good to me! Here's how I did it:I believe that Calculus questions aren't really doing no good on the topic :P.
I'd like to offer a question of my own though, if I may, to get the brain going;
(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fi.imgur.com%2FJ4IoJFj.jpg&hash=dfe004cb9d9395d4e902fd5b2dd7c659)
(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fi.imgur.com%2FGLNCdDP.jpg&hash=a2842dbe7e0a505729881b1c4bbf1372) 64/125? xD
Paint skills :ohttps://emps-world.net/forum/index.php?topic=3908.0
I got a problem with maths to be honest and I really do want to give some of the questions I couldn't solve but maths language in English is way too complicated to me as well as for google translator lol
I'll try my best translating them out and oh well, you guys might could gimme a hand :)
Paint skills :o^^ Same problem.
I got a problem with maths to be honest and I really do want to give some of the questions I couldn't solve but maths language in English is way too complicated to me as well as for google translator lol
I'll try my best translating them out and oh well, you guys might could gimme a hand :)
Here it isbefore we go on though, could you explain how we do this, since I tried a few methods, but all failed(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fpuu.sh%2Fh9q0I%2F1e11d73b64.png&hash=5902124062c9223df4e7878a6bbcc294)
Gladly ^^Here it isbefore we go on though, could you explain how we do this, since I tried a few methods, but all failed(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fpuu.sh%2Fh9q0I%2F1e11d73b64.png&hash=5902124062c9223df4e7878a6bbcc294)
Any attempt yet? Already got the answers :D.Those questions are some next level ****
(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fi.imgur.com%2FXWaJizy.png&hash=304f95593ff313f45814d1d83d5c153b)Any attempt yet? Already got the answers :D.Those questions are some next level ****
Easier pls :s
old for u. new to me 19 hhhh(https://emps-world.net/forum/proxy.php?request=http%3A%2F%2Fi.imgur.com%2FXWaJizy.png&hash=304f95593ff313f45814d1d83d5c153b)Any attempt yet? Already got the answers :D.Those questions are some next level ****
Easier pls :s
#Old, I know
hint: try to get both equalities to the form a^(something)=a^(somethingelse), and that the log base a of both sides. This should leave you with a system of equations that can easily be solved.Any attempt yet? Already got the answers :D.Those questions are some next level ****
Easier pls :s
because that totally made it easier for him :kappa:hint: try to get both equalities to the form a^(something)=a^(somethingelse), and that the log base a of both sides. This should leave you with a system of equations that can easily be solved.Any attempt yet? Already got the answers :D.Those questions are some next level ****
Easier pls :s
Another hint: this can be done by changing for example 27 to 3^{3}, and subsequently using power rules to factor the 3 into the current exponent.
hint: try to get both equalities to the form a^(something)=a^(somethingelse), and that the log base a of both sides. This should leave you with a system of equations that can easily be solved.Any attempt yet? Already got the answers :D.Those questions are some next level ****
Easier pls :s
Another hint: this can be done by changing for example 27 to 3^{3}, and subsequently using power rules to factor the 3 into the current exponent.
Close. you error is in calculating x after you find y.hint: try to get both equalities to the form a^(something)=a^(somethingelse), and that the log base a of both sides. This should leave you with a system of equations that can easily be solved.Any attempt yet? Already got the answers :D.Those questions are some next level ****
Easier pls :s
Another hint: this can be done by changing for example 27 to 3^{3}, and subsequently using power rules to factor the 3 into the current exponent.
You haven't added my previous answer to the archive btw >:( >:( >:( >:( >:(
('ll try to solve the latest questions soon-ish)
(also since I do math in german I'll have to read a bit on what constant terms of expansion are cuz languages)
edit:this took longer than expected because I am a moron who forgot how exponents work, but I hope I made no mistakes
this time:
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Yep, I always do mistakes like that, even in exams, is the answer 24? since if y=6 and x=3y+3 then x=3*6+3=21 and then 2*21-3*6=24Congratz.
edit: I even fixed it in my text book
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